Question

Re arrange in descending order
$\frac{3}{6}:\frac{6}{9}:\frac{1}{3};\frac{4}{9}$

Answer 1

$\frac{3}{6}=\frac{1}{2}\times \frac{9}{9}=\frac{9}{18}$

$\frac{6}{9}=\frac{2}{3}\times \frac{3}{3}=\frac{6}{9}\times \frac{2}{2}=\frac{12}{18}$

$\frac{1}{3}=\frac{1}{3}\times \frac{3}{3}=\frac{3}{8}\times \frac{2}{2}=\frac{6}{18}$

$\frac{4}{9}=\frac{4}{9}\times \frac{1}{1}=\frac{4}{9}\times \frac{2}{2}=\frac{8}{18}$

$\therefore \frac{12}{18}>\frac{9}{18}>\frac{8}{18}>\frac{6}{18}$

So, the descending order is:

$\frac{6}{9}>\frac{3}{6}>\frac{4}{9}>\frac{1}{3}$