Re 1-i2-3-1-A- 1 - 5B- -1 - 5C- 1 - 10D- -1 - 10

The correct option is B 1/5 Re [ (1+i)^2/3 i] = Re[ (2i/3 i) (3+i/3+i) ] =Re [ 6i 2/9+1] = Re [ 2/10 + 6/10 i ] = 1/5. ...

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Re 1+i2/3-1=A...

Question

Re $\frac{(1 + i)^{2}}{3 - i} =$

-1/5

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1/10

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