Reaction of 2-butane with acidic KMnO $_{4}$ gives

CH $_{3}$ CHO

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HCOOH

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CH $_{3}$ CH $_{2}$ OH

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CH $_{3}$ COOH

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Solution

The correct option is D
CH $_{3}$ COOH

$C H_{3} - C H$ $C H - C H_{3} K M n O_{4} / H^{+} - ------- \to 2 C H_{3} C O O H$

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Similar questions

Reaction of 2-butane with acidic KMnO $_{4}$ gives

2

B r_{2}

K M n O_{4}

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