Question

Reaction of ammonia with excess Cl₂ gives:

• A. ${\mathrm{NH}}_4\mathrm{Cl}\mathrm{and}{\mathrm{N}}_2$
• B. ${\mathrm{NH}}_4\mathrm{Cl}\mathrm{and}\mathrm{HCl}$
• C. ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$
• D. ${\mathrm{NCl}}_3\mathrm{and}{\mathrm{NH}}_4\mathrm{Cl}$

Answer 1

The correct option is C

${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$

Explanation for correct answer:-

Option (C) ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$

• Chlorine when reacts with excess Ammonia forms Ammonium chloride and Nitrogen:

$\underset{\mathrm{Ammonia}}{8{\mathrm{NH}}_3\left(\mathrm{g}\right)\left(\mathrm{excess}\right)}+\underset{\mathrm{Chlorine}}{3{\mathrm{Cl}}_2\left(\mathrm{g}\right)}\to \underset{\mathrm{Ammonium}\mathrm{chloride}}{6{\mathrm{NH}}_4\mathrm{Cl}\left(\mathrm{s}\right)}+\underset{\mathrm{Nitrogen}}{{\mathrm{N}}_2\left(\mathrm{g}\right)}$

• But when Ammonia reacts with excess of Chlorine then it forms Nitrogen trichloride$\left({\mathrm{NCl}}_3\right)$ and Hydrochloric acid:

$\underset{\mathrm{Ammonia}}{{\mathrm{NH}}_3\left(\mathrm{g}\right)}+\underset{\mathrm{Chlorine}}{3{\mathrm{Cl}}_2\left(\mathrm{g}\right)\left(\mathrm{excess}\right)}\to \underset{\mathrm{Nitrogen}\mathrm{trichloride}}{{\mathrm{NCl}}_3\left(\mathrm{s}\right)}+\underset{\mathrm{Hydrochloric}\mathrm{acid}}{3\mathrm{HCl}\left(\mathrm{g}\right)}$

• Hence it is the correct option.

Therefore, Reaction of ammonia with excess Cl₂ gives option (C) ${\mathrm{NCl}}_3\mathrm{and}\mathrm{HCl}$