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Observations of Chemical Changes

Reaction of C...

Question

Reaction of $C a (O H)_{2}$ with excess of $C O_{2}$ forms

C a C O_{3}

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C a (H C O_{3})_{2}

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C a C O_{3}

and

H_{2} O

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Both (a) and (b)

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Solution

The correct option is B $C a (H C O_{3})_{2}$
$C O_{2}$ readily reacts with alkalis to form the corresponding carbonate.
If $C O_{2}$ is in excess, it forms the corresponding hydrogen carbonate.
Here, $C O_{2}$ reacts with calcium hydroxide to form calcium carbonate. Thus, on excess of $C O_{2}$ it forms calcium bicarbonate.
This reaction is the basis of the limewater test for $C O_{2}$ gas.

$C a (O H)_{2} (a q) + C O_{2} (g) \to C a C O_{3} (s) + H_{2} O (l)$
$C a C O_{3} (s) + H_{2} O (l) + C O_{2} (g) \to C a (H C O_{3})_{2} (a q)$

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Similar questions

C a (O H)_{2} + C O_{2} \to C a C O_{3} + H_{2} O

C O_{2}

C a (O H)_{2} + C O_{2} \to C a C O_{3} + H_{2} O

Which type of reaction is this? (Include subcategory if applicable)

Ca(OH)₂ + CO₂ ----> CaCO₃ + H₂O

C a (O H)_{2} + C O_{2} ⟶ C a C O_{3} + H_{2} O percentage yield = 30%

200 mL

\frac{N}{10}

C a (O H)_{2}

2.2 g

C O_{2}

C a C O_{3}

2 g

C O_{2}

C O_{2}

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