Reaction of monochloro ethane is hydrolysed with aqueous KOH as follows:
$C H_{3} C H_{x} C l + a q . K O H \to C_{2} H_{y} O H + K C l$
Find x and y.

x = 1, y = 3

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x = 1, y = 5

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x = 2, y = 3

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x = 2, y = 5

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Solution

The correct option is C $x = 2, y = 5$
The balaned chemical reaction is as follows:
$C H_{3} C H_{2} C l + a q . K O H \to C_{2} H_{5} O H + K C l$
Thus, by looking at the equation, we can see that x $=$ 2 and y $=$ 5.

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If $\frac{3}{x + y} + \frac{2}{x - y} = 2 a n d \frac{9}{x + y} - \frac{4}{x - y} = 1$ then

(a) x= $\frac{1}{2}$ ,y= $\frac{3}{2}$ (b) x= $\frac{5}{2}$ ,y= $\frac{1}{2}$ (c)x= $\frac{3}{2}$ ,y= $\frac{1}{2}$ (d) x= $\frac{1}{2}$ ,y= $\frac{5}{2}$

Q. Solve the following pair of equations:

\frac{5}{x - 1} + \frac{1}{y - 2} = 2

\frac{6}{x - 1} - \frac{3}{y - 2} = 1

(Where

x \neq 1, y \neq 2)

Q. If

x^{2} y = 2 x - y

and

x^{2} < 1

, then

a \times [x + \frac{1}{3} x^{3} + \frac{1}{5} x^{5} + . . .] = y + \frac{1}{3} y^{3} + \frac{1}{5} y^{5} + . . .

Find

a

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Reaction of monochloro ethane is hydrolysed with aqueous KOH as follows:CH3CHxCl+aq.KOH→C2HyOH+KClFind x and y.

The correct option is C x=2,y=5The balaned chemical reaction is as follows:CH3CH2Cl+aq.KOH→C2H5OH+KClThus, by looking at the equation, we can see that x = 2 and y = 5.

Reaction of monochloro ethane is hydrolysed with aqueous KOH as follows:
$C H_{3} C H_{x} C l + a q . K O H \to C_{2} H_{y} O H + K C l$
Find x and y.

The correct option is C $x = 2, y = 5$
The balaned chemical reaction is as follows:
$C H_{3} C H_{2} C l + a q . K O H \to C_{2} H_{5} O H + K C l$
Thus, by looking at the equation, we can see that x $=$ 2 and y $=$ 5.