Reaction of trans−2−phenyl−1−bromo-cyclopentane on reaction with alcoholic KOH produces:
A
4−phenylcyclopentene
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B
2−phenylcyclopentene
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C
1−phenylcyclopentene
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D
3−phenylcyclopentene
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Solution
The correct option is A3−phenylcyclopentene Bi molecular elimination reactions takes place when two groups to be eliminated are trans and lie in one plane with two carbon atoms to which they are attached. So D is the correct option.