Reaction of $t r a n s - 2 - p h e n y l - 1 - b r o m o c y c l o p e n t a n e$ on reaction with alcoholic $K O H$ produces (major):

4 - p h e n y l c y c l o p e n t e n e

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2 - p h e n y l c y c l o p e n t e n e

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1 - p h e n y l c y c l o p e n t e n e

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3 - p h e n y l c y c l o p e n t e n e

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Solution

The correct option is A $4 - p h e n y l c y c l o p e n t e n e$
It follows E2 mechanism. Hughes and Ingold proposed that bimolecular elimination reactions take place when the two groups to be eliminated are trans and lie in one plane with the two carbon atoms to which they are attached. E2 reactions are stereoselectively trans
The correct is option D.

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