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Standard XII

Chemistry

Neighbouring Group Participation

Reaction of x...

Question

Reaction of $x g$ of $S n$ with $H C l$ quantitatively produced a salt. Entire amount of the salt reacted with $y g$ of
nitrobenzene in the presence of required amount of $H C l$ to produce $1.29 g$ of an organic salt (quantitatively).
(Use Molar masses (in $g m o l^{- 1}$ ) of $H, C, N, O, C l$ and $S n$ as

The value of $x$ is .

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Solution

$S n + 2 H C l \to S n C l_{2} + H_{2}$
Moles of $S n = \frac{x}{119}$
Moles of nitrobenzene $= \frac{x}{119} \times \frac{1}{3}$
Moles of anilium chloride $= \frac{x}{119} \times \frac{1}{3}$
Moles of nitrobenzene $= \frac{x}{357}$
$\frac{y}{123} = \frac{x}{357}$ ...(1)
Moles of anilium chloride $= \frac{x}{357}$ ...(2)
$\frac{1.29}{129} = \frac{x}{357}$
$x = 3.57$

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Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively). (Use Molar masses (in g mol–1) of H, C, N, O, Cl and Sn as The value of x is .

Sn+2HCl→SnCl2+H2 Moles of Sn=x119 Moles of nitrobenzene =x119×13 Moles of anilium chloride =x119×13 Moles of nitrobenzene =x357 y123=x357 ...(1) Moles of anilium chloride =x357 ...(2) 1.29129=x357 x=3.57