Reaction which produces a yellow precipitate is :

N a O H (a q) + H C l (a q) \to N a C l (s) + H_{2} O

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N a O H (a q) + B a C l (a q) \to B a O H (s) + N a C l (a q)

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P b (N O_{3})_{2} (a q) + 2 K I (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)

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C u O (s) + M g (s) \to C u (s) + M g O (s)

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4 F e + 3 O_{2} \to 2 F e_{2} O_{3}

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Solution

The correct option is C $P b (N O_{3})_{2} (a q) + 2 K I (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)$
The reaction $P b (N O_{3})_{2} (a q) + 2 K I (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)$ produces a yellow precipitate of lead diiodide.

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Similar questions

Q. Identify the type of the following reaction:

2 K I (a q) + P b (N O_{3})_{2} (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)

Q. What is one of the spectator ions in the following reaction?

P b (N O_{3})_{2} (a q) + 2 K I (a q) \to P b I_{2} (s) + 2 K N O_{3} (a q)

Given the reaction:-

$P b {(N O_{3})}_{2} (a q) + 2 K I \to P b I_{2} (s) + 2 K N O_{3} (a q)$ What is the mass of $P b I_{2}$ that will precipitate if 10.2 g of $P b {(N O_{3})}_{2}$ is mixed with 5.73 g of $K I$ in a sufficient quantity of $H_{2} O$ ?

NaOH (aq) + HCl (aq) \to NaCl (aq) + H_{2} O (l)

The above reaction is a:

Complete and balance the following chemical equations :

(a) $Z n (s) + H C l (a q) \to$

(b) $N a_{2} C O_{3} (s) + H C l (a q) \to$

(d) $N a O H (a q) + H C l (a q) \to$

(e) $C u O (s) + H C l (a q) \to$

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Reaction which produces a yellow precipitate is :

The correct option is C Pb(NO3)2(aq)+2KI(aq)→2KNO3(aq)+PbI2(s) The reaction Pb(NO3)2(aq)+2KI(aq)→2KNO3(aq)+PbI2(s) produces a yellow precipitate of lead diiodide.

The correct option is C $P b (N O_{3})_{2} (a q) + 2 K I (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)$
The reaction $P b (N O_{3})_{2} (a q) + 2 K I (a q) \to 2 K N O_{3} (a q) + P b I_{2} (s)$ produces a yellow precipitate of lead diiodide.