Question

Reactions are listed in List-I. Match the result of the respective reactions with the appropriate options listed in List-II.

Answer 1

$\left(A\right)P_4+8SOC{l}_2\to 4PC{l}_3+4S{O}_2+S_{2}C{l}_2$ (dimeric halide)

$S{O}_2$ is an acidic oxide. It reacts with water to give sulphurous acid.

$\left(B\right)2KI+H_{2}O+O_3\to 2KOH+I_2+O_2$

$\left(C\right)2S{O}_2+O_2\stackrel{V_2{O}_5/heat}{⟶}2S{O}_3;S{O}_3\left(s\right)$ exists as $(S{O}_3{)}^{3-}$. It exists as a cyclic form at room temperature.

It is an acidic oxide. It reacts with water to form sulphuric acid.

$\left(D\right)3H_{3}P{O}_3+3B{r}_2\stackrel{heatinasealedtube}{⟶}(HP{O}_3{)}_3+6HBr$

$(HP{O}_3{)}_3$ is trimetaphosphoric acid which exists in cyclic form at room temperature.