Question

Reactivity of $HCHO$ with the following G.R in the decreasing order is:
i. $PhMgBr$ ii. $PhC{H}_{2}MgBr$
iii. & iv. (Ref. image)

• A. $\left(iv\right)>\left(iii\right)>\left(ii\right)>\left(i\right)$
• B. $\left(i\right)>\left(ii\right)>\left(iii\right)>\left(iv\right)$
• C. $\left(iii\right)>\left(ii\right)>\left(i\right)>\left(iv\right)$
• D. $\left(ii\right)>\left(iii\right)>\left(i\right)>\left(iv\right)$

Answer 1

Answer: (A)

$\left(iv\right)>\left(iii\right)>\left(ii\right)>\left(i\right)$

option A is correct due to positive charge stability.