Reactivity of Tertiary H, Secondary H and Primary H towards elimination is:

T e r t . > S e c . > P r i .

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S e c . > T e r t . > P r i .

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S e c . > P r i . > T e r t .

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P r i . > S e c . > T e r t .

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Solution

The correct option is A $T e r t . > S e c . > P r i .$
The order of reactivity for the various hydrogens is $3^{\circ} > 2^{\circ} > 1^{\circ}$ and can be explained using hyperconjugation.

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