Reactivity order of halides for dehydrohalogenation is :

R - F > R - C l > R - B r > R - I

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R - I > R - B r > R - C l > R - F

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R - I > R - C l > R - B r > R - F

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R - F > R - I > R - B r > R - C l

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Solution

The correct option is B $R - I > R - B r > R - C l > R - F$
F, Cl, Br, I belong to the same group orderly. Atomic radii go on increasing as the nuclear charge increases in proceeding downwards in a group.
The decreasing order of bond length $C - I > C - B r > C - C l > C - F$

The order of bond dissociation energy $R - F > R - C l > R - B r > R - I$ .

During dehydrohalogenation $C - I$ bond breaks more easily than $C - F$ bond.
So reactivity order of halides. $R - I > R - B r > R - C l > R - F$

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