Question

Read the below given conversion.

N${}_2$+8e${}^{–}$+8H${}^{+}$+16ATP $\to$ A+B+16ADP +16Pi

Identify A and B and select the correct option.

• A. A – 2NH${}_3$, B – O${}_2$
• B. A – NO${}_3^{-}$ , B – H${}_2$O
• C. A – 2NH${}_3$, B – H${}_2$
• D. A – NO${}_3^{-}$ , B – H${}_2$O

Answer 1

The correct option is C A – 2NH${}_3$, B – H${}_2$

In N${}_2$ fixation, one molecule of nitrogen converts into two molecules of ammonia and H${}_2$. So A is 2NH${}_3$ and B is H${}_2$. Nitrate is formed during nitrification process.