Read the following reaction
(i) $C H_{3} C O O N a + N a O H C a O - - \to C H_{4} + N a_{2} C O_{3}$
(ii) $C H_{3} C O O N a + C_{2} H_{5} O H A c i d - - \to C H_{3} C O O C_{2} H_{5} + H_{2} O$
(iii) $C H_{3} C O O C_{2} H_{5} + N a O H ⟶ C H_{3} C O O N a + C_{2} H_{5} O H$
(iv) $2 C H_{3} C O O H + 2 N a ⟶ 2 C H_{3} C O O N a + H_{2}$
Which of the above represents(s) esterification reaction?

only (i)

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only (ii)

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(i) and (iii)

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(ii) and (iv)

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Solution

The correct option is D only (ii)
the process of combining an organic acid (RCOOH) with an alcohol (ROH) to form an ester (RCOOR) and water.In words conversion of an acid into an ester by combination with an alcohol and removal of a molecule of water.
Hence it is seen in second one only.Hence option B is the correct answer.

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Similar questions

C H_{3} C O O N a + N a O H C a O - - \to C H_{4} + N a_{2} C O_{3}

C H_{3} C O O H + C_{2} H_{5} O H H_{2} S O_{4} - --- \to C H_{3} C O O C_{2} H_{5} + H_{2} O

2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2}

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

C H_{3} C O O N a + N a O H C a O - - \to C H_{4} + N a_{2} C O_{3}

C H_{3} C O O H + C_{2} H_{5} O H H_{2} S O_{4} - --- \to C H_{3} C O O C_{2} H_{5} + H_{2} O

2 C H_{3} C O O H + 2 N a \to 2 C H_{3} C O O N a + H_{2}

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

{CH}_{3} COOH + {Na}_{2} {CO}_{3} \to

C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C O O N a + C_{2} H_{5} O H

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