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Introduction to Morgan's Experiments

Read the give...

Question

Read the given passage and answer the following question.

In fruit flies, normal-sized, solid-colored body and red eyes are wild-type (normal) traits. Flies can be assumed to have these traits unless otherwise stated. Fruit flies from a strain with purple eyes are crossed with fruit flies from a strain with dwarf bodies to produce F $_{1}$ generation which then undergoes selfing to produce F $_{2}$ generation.
The allele resulting in purple eyes is located near an allele resulting in streaks across the body, on the same chromosome. The streaked body phenotype is recessive. Crosses are performed with flies from purebred lines, which are wild type for all other traits.

The number of F $_{2}$ flies with dwarf, red-eyed phenotype are

1 in 3

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1 in 4

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1 in 16

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3 in 16

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9 in 16

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Solution

The correct option is D 3 in 16
According to the table, a number of $F_{2}$ flies with the dwarf, red-eyed phenotype is 95 out of total 548. This makes their ratio 95/548 x 16= 2.77 or 3 out of 16. Thus, the correct answer is option D.

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Similar questions

Cross 1	Cross 2
Parents Bar-eyed female $\times$ Wild type male	Parents Wild-type Female $\times$ Bar eyed Male
$F_{1}$ 53 Bar-eyed males 47 Bar-eyed females	$F_{1}$ 48 Wild-type males 52 Bar-eyed females
Cross 4 $F_{1}$ flies from cross 1 were mated	Cross 4 $F_{1}$ flied from cross 2 were mated
$F_{2}$ 22 Bar-eyed males 51 Bar-eyed females 27 wild-type males 0 Wild-type females	$F_{2}$ 25 Bar-eyed males 26 Bar-eyed females 27 Wild-type males 25 Wild-type females

Read the passage and answer the following question:
An experiment is carried out to explore the inheritance of the bar-eyed trait in fruit flies. Homozygous bar-eyed and wild-type flies are mated, producing two

F_{1}

generations. Then crossing of

F_{1}

offsprings produces two

F_{2}

generations. Here are the data from those 4 crosses which records one hundred offspring from each cross.
Which of the following would be the genotype for a bar-eyed female in the

F_{1}

generation in cross 1?

Q. Read the passage and answer the following question.
An experiment is carried out to explore inheritance of the bar-eyed trait in fruit flies. Homozygous bar-eyed and wild-type flies are mated, producing two

F_{1}

generations. Then crossing of

F_{1}

offsprings produces two

F_{2}

generations.
Here are the data from those 4 crosses which records one hundred offspring from each cross.
Which of the following is the the pattern of inheritance for bar-eyed?

Q. True breeding red-eyed Drosophila flies with plain thoraxes were crossed with pink eyed flies with striped thoraxes.
Red eye plain thorax

\times

Pink eye striped thorax
The

F_{1}

flies were then crossed against the double recessive
The following

F_{2}

generation resulted from the cross:

$80$	$16$	$12$	$92$
Red eye	Red eye	Pink eye	Pink eye
Plain thorax	Striped thorax	Plain thorax	Striped thorax

What percentage number of recombinants resulted from the test cross?

Q. In Drosophila melanogaster, cherub wings

(c h (

, black body

(b)

and cinnabar eyes

(c n)

are recessive to their corresponding alleles (represented as

c h +, b +

and

c n +

, respectively) and are all located on chromosomes

2

. Homozygous wild type flies were mated with cherub, black and cinnabar flies and the resulting

F 1

females were test crossed with cherub, black and cinnabar males. The following progeny were produced from the test cross:

$c h b + c n$	$110$
$c h + b + c n +$	$780$
$c h + b c n$	$70$
$c h + b + c n$	$6$
$c h b c n$	$769$
$c h b + c n +$	$60$
$c h + b c n +$	$111$
$c h b c n +$	$9$
Total	$1915$

Of these three genes, which one is in the middle?

Q. In fruit flies, allele for long wing is dominant to the allele for vestigial wing. When heterozygous long winged flies were crossed with vestigial winged flies, 192 offsprings were produced. Of these 101 had long wing & 91 had vestigial wings.
If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been

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The correct option is D 3 in 16According to the table, a number of F2 flies with the dwarf, red-eyed phenotype is 95 out of total 548. This makes their ratio 95/548 x 16= 2.77 or 3 out of 16. Thus, the correct answer is option D.

The correct option is D 3 in 16
According to the table, a number of $F_{2}$ flies with the dwarf, red-eyed phenotype is 95 out of total 548. This makes their ratio 95/548 x 16= 2.77 or 3 out of 16. Thus, the correct answer is option D.