Reagent is:

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HCl and H₂O

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KOH in C₂ H₅ OH

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Solution

The correct option is C
KOH in C₂ H₅ OH

(c) $R - C H_{2} - C C l_{2} - R K O H + C_{2} H_{5} O H - ---------- \to R - C \equiv C - R$

This reaction is an example of dehydrohalogenation.

Hence, alcoholic KOH is used as a reagent.

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{C H}_{3} - {C H}_{2} - O H R e a g e n t - ---- \to {C H}_{3} C H O

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