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Question

Real numbers a and b satisfy the equations 3a=81b+2 and 125b=5a3 The value of ab is

A
17
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B
9
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C
12
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D
60
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Solution

The correct option is C 60
Given,3a=81b+23a=34b+8
a=4b+8a4b=8 ...(i)
and 125b=5a353b=5a3
3b=a3a3b=3 ...(ii)
On adding (i) and (ii), we get
a4b=8
a+3b=3––––––––
b=5
b=5
On putting b=5 in (i), we get
a=8+4b=8+4×(5)a=12
Now, ab=(5)(12)=60
Hence, Option D is correct.

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