CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Rearrange the digits of the number 2,01,53,007 to get the largest and the smallest number. The difference in the place values of 2 in these two numbers is


A

8000

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

18000

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

180000

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

18000


Explanation for the correct option:

Option C: 18000

The number given is 2,01,53,007.

Step I: Finding the smallest number.

Arranging the digits of the given number in increasing order we will get the smallest number.

Also, zero cannot be placed as the first digit as zero placed before the digits have no value.

So, instead we will place 1 as the first digit followed by 0 and then 2.

Therefore, the smallest number is 10002357.

Step II: Finding the largest number.

Arranging the digits of the given number in decreasing order will give the largest number.

Therefore, the largest number is 75321000.

Step III: Finding the place value of 2 in the smallest and greatest number.

In the smallest number 10002357, the digit 2 is present at the thousands place.

Hence, the place value of 2 is 2000.

In the largest number 75321000, the digit 2 is present at the ten-thousands place.

Hence, the place value of 2 is 20,000.

Step IV: Finding the difference between the place values of 2.

Difference=20,000-2000

=18,000.

Therefore, the difference in the place values of 2 in these two numbers is 18,000.

Hence, the correct option is option C.


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Forming largest number using 9 up to seven digits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon