Question

Rearrange the following (I to IV) in the order of increasing masses.
(I) 0.5 moles of $O_3$
(II) $0.5$ g-atom of oxygen
(III) $3.011\times {10}^{23}$ molecules of $O_2$
(IV) $5.6\text{L}$ of $C{O}_2$ at STP

• A. II < IV < III < I
• B. II < I < IV < III
• C. IV < II < III < I
• D. I < II < III < IV

Answer 1

The correct option is A II < IV < III < I

(I) 0.5 moles $O_3=24\text{g}$ of $O_3$

(II) $0.5\text{g}$ atom of oxygen = $8\text{g}$

(III) $\frac{3.011\times {10}^{23}}{6.022\times {10}^{23}}\times 32\text{g}{O}_2=16g$

(IV) $\frac{5.6}{22.4}\times 44\text{g}C{O}_2=11\text{g}C{O}_2$