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Question

Rearrange the following ($$I$$ to $$IV$$ ) in the order of increasing masses: 
I) $$0.5$$ mole of $$O_3$$
II) $$0.5\ gm$$ atom of oxygen
III) $$3.011 \times 10^{23}$$ molecules of $$O_2$$ 
IV) $$5.6$$ litre of $$CO_2$$ at $$1\ atm$$ and $$273\ K$$


A
II<IV<III<I
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B
II<I<IV<III
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C
IV<II<III<I
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D
I<II<III<IV
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Solution

The correct option is A $$II < IV < III < I$$
$$I) \text{ mass of substance} = \text{moles of substance}\times{\text{molar mass of substance}}$$

$$\text{mass of }O_3 = 0.5\times{48} = 24g$$

$$II) \text{ 1 gm atom} = 1\text{mole}$$

$$\text{mass of }O = 0.5\times{16} = 8g$$

$$III) \text{ 1 mole} = 6.022\times{10^{23}}\text{molecules}$$
$$\text{number of moles of }O_2 = \dfrac{3.011\times{10^{23}}}{6.022\times{10^{23}}} = 0.5$$
$$\text{mass of }O_2 = 0.5\times{32} = 16g$$

$$IV) \text{ volume of 1 mole at NTP} = 22.4L$$
$$\text{moles of }CO_2 = \dfrac{5.6}{22.4} = 0.25$$
$$\text{mass of }CO_2 = 0.25\times{44} = 11g$$

Chemistry

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