Question

# Rearrange the following ($$I$$ to $$IV$$ ) in the order of increasing masses: I) $$0.5$$ mole of $$O_3$$II) $$0.5\ gm$$ atom of oxygenIII) $$3.011 \times 10^{23}$$ molecules of $$O_2$$ IV) $$5.6$$ litre of $$CO_2$$ at $$1\ atm$$ and $$273\ K$$

A
II<IV<III<I
B
II<I<IV<III
C
IV<II<III<I
D
I<II<III<IV

Solution

## The correct option is A $$II < IV < III < I$$$$I) \text{ mass of substance} = \text{moles of substance}\times{\text{molar mass of substance}}$$$$\text{mass of }O_3 = 0.5\times{48} = 24g$$$$II) \text{ 1 gm atom} = 1\text{mole}$$$$\text{mass of }O = 0.5\times{16} = 8g$$$$III) \text{ 1 mole} = 6.022\times{10^{23}}\text{molecules}$$$$\text{number of moles of }O_2 = \dfrac{3.011\times{10^{23}}}{6.022\times{10^{23}}} = 0.5$$$$\text{mass of }O_2 = 0.5\times{32} = 16g$$$$IV) \text{ volume of 1 mole at NTP} = 22.4L$$$$\text{moles of }CO_2 = \dfrac{5.6}{22.4} = 0.25$$$$\text{mass of }CO_2 = 0.25\times{44} = 11g$$Chemistry

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