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Question

Rearrange the like terms:
7l3m221lm2n+28lm

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Solution

The given terms 7l3m2,21lm2n and 28lm can be rewritten as follows:

7l3m2=7×l×l×l×m×m21lm2n=7×3×l×m×m×n28lm=7×4×l×m

These terms have 7,l and m as common factors, therefore,

7l3m221lm2n+28lm=(7×l×l×l×m×m)(7×3×l×m×m×n)+(7×4×l×m)=7×l×m[(l×l×m)(3×m×n)+(4)](Combiningliketerms)=7lm(l2m3mn+4)

Hence, 7l3m221lm2n+28lm=7lm(l2m3mn+4).

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