Let us consider a circle with center O and two equal chords of a circle AB and CD.
We need to prove that ∠AOB=∠COD
In △ AOB and COD, we have
AO=CO (Radius of the circle)
BO=DO (Radius of the circle)
AB=CD (Equal chords)
By SAS criterion of congruence, we have
△AOB≅△COD
⇒∠AOB=∠COD