The correct option is B equal
Given−A&BaretwocongruentcircleswithequalchordsPQ&STrespectively.Toprovethat−PQ&STsubtendequalanglestothecentre.i.e∠PAQ=∠SBT.Proof−Weknowthatcongruentcircleshaveequalradii.∴AP=AQ=BS=BT=r.So,betweenΔPAQ&ΔBSTwehaveAP=AQ=BS=BT=randPQ=ST.∴BySSStest,ΔPAQ≅ΔBST⟹∠PAQ=∠SBT.SoPQ&STsubtendequalanglestothecentre.Q.E.D.Ans−OptionB.