Recently, the phenomenon of superconductivity has been observed at 95 K. This temperature is nearly equal to

- 288°F

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- 146°F

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- 368°F

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+178°F

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Solution

The correct option is A
- 288°F

$\frac{F - 32}{9} = \frac{K - 273}{5} \Rightarrow \frac{F - 32}{9} = \frac{95 - 273}{5} \Rightarrow= - 288^{\circ} F$

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