Question

Reciprocal of $\frac{-3}{4}$ is

(a) $\frac{4}{3}$

(b) $\frac{3}{4}$

(c) $\frac{-4}{3}$

(d) 0

Answer 1

Since, reciprocal of $\frac{a}{b}$ is $\frac{a}{b}$ [Since, $\frac{1}{\frac{a}{b}}=\frac{b}{a}$]
By, taking $a=-3$ and $b=4$, we get,
reciprocal of $\frac{-3}{4}$ is $\frac{-4}{3}$