Question

# Recorded data: Before$$:$$ $$CuO+$$porcelain boat$$=62.869\:g$$$$CaCl_2+$$U-tube$$=80.483\:g$$After:Porcelain boat$$+$$contents $$=54.869\:g$$$$CaCl_2+U$$-tube$$=89.483\:g$$Reactions:$$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$$ then $$H_2(g)+CuO(s)\rightarrow H_2O(g)+Cu(s)$$What conclusion can you draw after the completion of  this experiment?

A
Hydrogen diffuses faster than oxygen
B
Hydrogen is lighter than oxygen
C
The molar mass of oxygen is 32g/mol.
D
Water is a triatomic molecule with polar characteristics
E
Water is formed from hydrogen and oxygen in a ratio of 1:8, by mass.

Solution

## The correct option is E Water is formed from hydrogen and oxygen in a ratio of $$1:8$$, by mass.Mass of $$\displaystyle CaCl_2 + U$$ tube $$\displaystyle = 80.483 \:g$$Mass of $$\displaystyle CaCl_2 + U$$ tube $$\displaystyle + H_2O= 89.483 \:g$$.Mass of water $$\displaystyle = 89.483-80.483 = 9 \:g$$The molar mass of water is 18 $$g/mol$$9 $$g$$ water corresponds to $$\displaystyle \dfrac {9 \:g}{18\:g/mol}=0.5 \:mol$$.1 $$mol$$ of $$\displaystyle H_2$$  gives 1 $$mol$$ of $$\displaystyle H_2O$$ 0.5 $$mol$$ of $$\displaystyle H_2$$  will give 0.5 $$g$$ of $$\displaystyle H_2O$$ The molar mass of $$\displaystyle H_2$$  is 2 $$g/mol$$.Mass of $$\displaystyle H_2 = 2 \:g/mol \times 0.5 mol=1 \:g$$ Hence, 1 gram of hydrogen were used in the formation of the water as product.Mass of $$\displaystyle CuO +$$  porcelain boat $$\displaystyle = 62.869 \:g$$Mass of $$\displaystyle Cu +$$   porcelain boat $$\displaystyle = 54.869 \:g$$Mass of oxygen $$\displaystyle = 62.869-54.869 = 8 \:g$$Hence, water is formed from hydrogen and oxygen in a ratio of 1:8, by mass.Chemistry

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