Rectangle $A B C D$ shown in the figure above has width $w$ and length $l$ that is twice the width. If $w = 2$ , calculate the area of the rectangle.

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Solution

The correct option is C $8$
We know area of a rectangle is length $\times$ width
Given, width is $2$ and length is twice the width, so length will be $2 \times 2 = 4$
Area of rectangle will be $=$ $(2 \times 4) = 8$

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Rectangle ABCD shown in the figure above has width w and length l that is twice the width. If w=2, calculate the area of the rectangle.

The correct option is C 8We know area of a rectangle is length × widthGiven, width is 2 and length is twice the width, so length will be 2×2=4Area of rectangle will be = (2×4)=8

Rectangle $A B C D$ shown in the figure above has width $w$ and length $l$ that is twice the width. If $w = 2$ , calculate the area of the rectangle.

The correct option is C $8$
We know area of a rectangle is length $\times$ width
Given, width is $2$ and length is twice the width, so length will be $2 \times 2 = 4$
Area of rectangle will be $=$ $(2 \times 4) = 8$