Reddish-brown (chocolate) ppt. is formed with :

C u^{2 +}

and

F e {(C N)}_{6}^{4 -}

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B a^{2 +}

and

S O_{4}^{2 -}

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P b^{2 +}

and

I^{-}

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None of these

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Solution

The correct option is A $C u^{2 +}$ and $F e {(C N)}_{6}^{4 -}$
Reddish-brown (chocolate) ppt. is formed with $C u^{2 +}$ and $F e {(C N)}_{6}^{4 -}$ which leads to the formation of $C u_{2} [F e {(C N)}_{6}]$ . Chocolate color insoluble compound.

Example : $2 C u S O_{4} + K_{4} [F e (C N)_{6}] ⟶ C u_{2} [F e (C N)_{6}] + 2 K_{2} S O_{4}$

So, the correct option is $A$

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Sodium hydroxide solution is added to the solution containing the Pb²⁺ ion.

Match the ions with their coloured precipitate.

A

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N H_{4} C l

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{N H}_{4} C l

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C u_{2} [F e (C N)_{6}]

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