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Electrochemical Series

Reddish brown...

Question

Reddish brown (chocolate) precipitate is formed by mixing solutions containing :

C u^{2 +}

and

[F e (C N)_{6}]^{3 -}

ions

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C u^{2 +}

and

[F e (C N)_{6}]^{4 -}

ions

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P b^{2 +}

and

S O_{4}^{2 -}

ions

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P b^{2 +}

and

I^{-}

ions

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Solution

The correct option is A $C u^{2 +}$ and $[F e (C N)_{6}]^{4 -}$ ions
Potassium ferrocyanide precipitates red-brown copper(II) ferrocyanide from $C u^{2 +}$ solutions:

$2 C u^{2 +} (a q) + [F e (C N)_{6}]^{4 -} (a q) \to C u_{2} [F e (C N)_{6}] (s)$

Hence, the reddish-brown precipitate is formed by mixing solutions containing $C u^{2 +}$ and $F e (C N)_{6}^{4 -}$ ions.

So, the correct option is $B$

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