Question

Reduce $\frac{-45}{30}$ to the standard form

Answer 1

We have $\frac{-45}{30}$ = $\frac{-45÷3}{30÷3}$

= $\frac{-15}{10}$

=$\frac{-15÷5}{10÷5}$= $\frac{-3}{2}$

We had to divide twice First time by 3 and then by 5 This could also be done as $\frac{-45}{30}$ = $\frac{-45÷15}{30÷15}$= $\frac{-3}{2}$