Question

Reduce each of the following fractions to the lowest terms:
(i) $\frac{161}{207}$
(ii) $\frac{517}{799}$
(iii) $\frac{296}{481}$

Answer 1

(i) $\frac{161}{207}$
To reduce the given fraction to its lowest term, we will divide the numerator and the denominator by their HCF.

Now, we will find the HCF of 161 and 207.

∴ HCF = 23

Dividing the numerator and the denominator by the HCF, we get:

$\frac{161÷23}{207÷23}=\frac{7}{9}$


(ii) $\frac{517}{799}$
To reduce the given fraction to its lowest term, we will divide the numerator and the denominator by their HCF.
Now, we will find the HCF of 517 and 799.

∴ HCF = 47

Dividing the numerator and the denominator by the HCF, we get:

$\frac{517÷47}{799÷47}=\frac{11}{17}$

(iii) $\frac{296}{481}$
To reduce the given fraction to its lowest term, we will divide the numerator and the denominator by their HCF.
Now, we will find the HCF of 296 and 481.



∴ HCF = 37

Dividing the numerator and the denominator by the HCF, we get:

$\frac{296÷37}{481÷37}=\frac{8}{13}$