Reduce 2 a2-2 a c-3 a b-3 b c-3 a2-3 a c-2 b b-2 b c

The correct option is A 2a + 3b/3a 2b The given fraction is 2a^2 2ac + 3ab 3bc/3a^2 3ac 2ab + 2bc It could be written as (2a + 3b)× (a c)/(3a 2b) ...

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Properties of Conjugate of a Complex Number

Reduce 2 a2-2...

Question

Reduce $\frac{2 a^{2} - 2 a c + 3 a b - 3 b c}{3 a^{2} - 3 a c - 2 a b + 2 b c}$

$\frac{2 a + 3 b}{3 a - 2 b}$

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$\frac{3 a + 2 b}{2 a - 3 b}$

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$\frac{a + 3 b}{3 a - b}$

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$\frac{3 a + b}{a - 2 b}$

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Solution

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Similar questions

12 a^{3} b c^{2}

12 a^{3} b c

12 a^{2} b c

2 a b + 3 a c + 2 a c

(a + b)^{2} + (a - b)^{2}

2 a + 2 b

2 a - 2 b

2 a^{2} + 2 b^{2}

2 a^{2} + 2 b^{2}

(a + b) (2a – 3b + c) – (2a – 3b) c = $2 a^{2}$ – $2 b^{2}$ – ab + 4bc – 2ac.

a + b + c = 0

\frac{(b + c)^{2}}{3 b c} + \frac{(c + a)^{2}}{3 a c} + \frac{(a + b)^{2}}{3 a b}

a^{3} + b^{3} + c^{3} = 3 a b c a n d a + b + c = 0

\frac{(b + c)^{2}}{3 b c} + \frac{(c + a)^{2}}{3 a c} + \frac{(a + b)^{2}}{3 a b} =

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