Question

Reduce $\frac{a^2+7a+10}{a+5}$ into its lowest form

• A. 1
• B. a+1
• C. 2
• D. a+2

Answer 1

The correct option is D

a+2

$a^2+7a+10=a^2+5a+2a+10=a(a+5)+2(a+5)=(a+2)(a+5)$
$\therefore$ $\frac{a^2+7a+10}{a+5}$ = $\frac{(a+2)(a+5)}{a+5}=(a+2).$