Question

Reduce in standard form $\frac{36}{-24}$

Answer 1

Writing the standard form:

The reduced form will be obtained when there is no negative sign in the denominator and factors are simplified.
Let,

find the HCF of $36$and $24.$

$$\begin{gathered} 36=2\times 2\times 3\times 3 \\ 24=2\times 2\times 2\times 3 \end{gathered}$$

So, H.C.F $(36,24)=2\times 2\times 3=\mathbf{12}$

Now, divide the numerator and denominator of$\frac{36}{-24}$ by $12$

.$$\begin{gathered} =(\frac{36}{12})÷(\frac{-24}{12}) \\ =\frac{3}{-2} \\ =\frac{\mathbf{-}\mathbf{3}}{\mathbf{2}} \end{gathered}$$
Thus, the reduced standard form of $\frac{36}{-24}$is $\frac{\mathbf{-}\mathbf{3}}{\mathbf{2}}$