Question

Reduce $\sqrt[4]{42}$, $\sqrt[3]{33}$, $\sqrt[5]{54^2}$ into surds of the same order.

Answer 1

L.C.M of $4,3$ and $5$ is $60$.
$\therefore \sqrt[4]{42}=\sqrt[4\times 15]{4\times 152^{15}}=\sqrt[60]{602^{15}}$

$\sqrt[3]{33}=\sqrt[3\times 20]{3\times 203^{20}}=\sqrt[60]{603^{20}}$

$\sqrt[3]{34^2}=\sqrt[5\times 12]{5\times 124^{2\times 12}}=\sqrt[60]{604^{24}}$