Question

Reduce the equation 3 x - 2 y + 6 = 0 to the intercept form and find the x and y intercepts.

Answer 1

$\text{The intercept form of equation is}$

$\frac{x}{a}+\frac{y}{b}=1$

$3x-2y+y=0$

$3x-2y=-6$

$\frac{-3x}{-6}-\frac{2y}{-6}=1$

$\frac{x}{\frac{-6}{3}}+\frac{y}{\frac{-6}{-2}}=1$

$\frac{x}{-2}+\frac{y}{3}=1$

$\Rightarrow \text{x-intercept}=a=-2$

$\text{y-intercept}=b=3$