Reduce the equation $x + y^{2} - 4 y + 5 = 0$ to the standard form.

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Solution

We have,

$x + y^{2} - 4 y + 5 = 0$

$y^{2} - 4 y + 4 - 4 + x + 5 = 0$
$(y - 2)^{2} + x + 1 = 0$

$\Rightarrow (y - 2)^{2} = - (x + 1)$

Therefore, this is the standard form.

Hence, this is the answer.

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Reduce the equation x+y2−4y+5=0 to the standard form.

We have, x+y2−4y+5=0 y2−4y+4−4+x+5=0(y−2)2+x+1=0 ⇒(y−2)2=−(x+1) Therefore, this is the standard form. Hence, this is the answer.

Reduce the equation $x + y^{2} - 4 y + 5 = 0$ to the standard form.

We have,

$x + y^{2} - 4 y + 5 = 0$

$y^{2} - 4 y + 4 - 4 + x + 5 = 0$
$(y - 2)^{2} + x + 1 = 0$

$\Rightarrow (y - 2)^{2} = - (x + 1)$

Therefore, this is the standard form.

Hence, this is the answer.