Question

Reduce the following equation to the normal form $x+5=0$.

Answer 1

$x+5=0$

Dividing both sides by normalizing factor $\sqrt{1^2+0^2}=1$

$x+5=0$

$x\cos \alpha +y\sin \alpha +5=0$

$\cos \alpha =1\sin \alpha =0p=-5$

$\alpha =0\alpha =0$

$\therefore x=-5$ is the normal form