Reduce the following equations to the normal form and find the values of $p$ and $α .$
$x - \sqrt{3} y - 12 = 0$

Open in App

Solution

$x - \sqrt{3} y - 12 = 0 x - \sqrt{3} y = 12 \frac{x}{2} - \frac{\sqrt{3}}{2} y = 6 x cos \frac{- π}{3} + y sin \frac{- π}{3} = 6 p = 6 α = - \frac{π}{3}$

Suggest Corrections

Similar questions

4 x + 3 y - 24 = 0

p, α

x + \sqrt{3} y - 4 = 0

x + y + \sqrt{2} = 0

x - y + 2 \sqrt{2} = 0

\sqrt{3} x - y + 5 = 0

p

α

Reduce the following equations to the normal form and find p and $α$ in each case :

$(i) x + \sqrt{3} y - 4 = 0$ $(i i) x + y + \sqrt{2} = 0$ $(i i i) x - y + 2 \sqrt{2} = 0$ $(i v) x - 3 = 0$ $(v) y - 2 = 0$

x + \sqrt{3} y + 4 = 0

y -

P

α

Join BYJU'S Learning Program