Question

Reduce the given algebraic fraction into the lowest form: $\frac{(a^6{b}^6+a^5{b}^5)}{a^3{b}^3}$, if x= $ab$

• A. $x^2+1$
• B. $x^2[x-1]$
• C. $[x+1]$
• D. $x^2[x+1]$

Answer 1

The correct option is D

$x^2[x+1]$

The given expression is: $\frac{(a^6{b}^6+a^5{b}^5)}{a^3{b}^3}$

$\Rightarrow$ $a^3{b}^3+a^2{b}^2$

Taking, $a^2{b}^2$ outside, $a^2{b}^2[ab+1]$

As, x= $ab$, this reduces to $x^2[x+1]$