Question

Reduce the given fraction into the lowest terms.
$\frac{42}{78}$

Answer 1

We have, $\frac{42}{78}$

The prime factorisation of

$42=2\times 3\times 7$

$78=2\times 39$

H.C.F of $(42,78)=2$

Now, we will divide the numerator and denominator by H.C.F to get the lowest term.

$\frac{42}{78}=\frac{(42÷2)}{(78÷2)}=\frac{21}{39}$

Thus, $\frac{21}{39}$ is the simplified fraction of $\frac{42}{78}$.