Question

Reduce to its simplest form:$\frac{2x^2-x-1}{x+1}=\frac{x^2+1}{-3x}$

Answer 1

$\frac{2x^2-x-1}{x+1}=\frac{x^2+1}{-3x}$

$\Rightarrow -3x(2x^2-x-1)=(x^2+1)(x+1)$

$\Rightarrow -6x^3+3x^2+3x-x^3+x^2+x+1$

$\Rightarrow -7x^3+2x^2+2x-1=0$

(or) $7x^3-2x^2-2x+1=0$.