Question

Reduce to the lowest terms

$\frac{x^2-y^2}{2x^{2}y-2x{y}^2}$, then the answer is $\frac{x+y}{2xy}$
If true then enter $1$ and if false then enter $0$

Answer 1

$Factorizing\frac{x^2-y^2}{2x^{2}y-2x{y}^2},=\frac{(x-y)(x+y)}{2xy(x-y)}=\frac{x+y}{2xy}$