Question

Reduced to lowest terms. $\frac{a^2-b^2}{ab}-\frac{ab-b^2}{ab-a^2}$ is equal to

• A. $\frac{a}{b}$
• B. $\frac{a^2-2b^2}{ab}$
• C. $a^2$
• D. $a-2b$
• E. None of these

Answer 1

Answer: (A)

$\frac{a}{b}$

$\frac{a^2-b^2}{ab}-\frac{b(a-b)}{a(b-a)}=\frac{a^2-b^2}{ab}+\frac{b^2}{ab}=\frac{a}{b}$.