Question

Reducing equation to simple from :-$\frac{6x+1}{3}=\frac{x-3}{6}$

Answer 1

given

$\frac{6x+1}{3}=\frac{x-3}{6}$

cross multiplying we get

$\Rightarrow 6(6x+1)-3(x-3)=36x+6-3x+9=0$

$\Rightarrow 33x+15=0$

$\Rightarrow x=-\frac{15}{33}=\frac{-5}{11}$ or $11x+5=0$