Reducing nature $N H_{3} < P H_{3} < A s H_{3} < S b H_{3}$
if true 1 else 0
1

Open in App

Solution

The correct option is A 1
As we move down the group, radius of elements increases and electronegativity decreases so ionic character of compounds increases and covalent nature decreases.
And as ionic character increase reducing nature increase so order is
$N H_{3} < P H_{3} < A s H_{3} < S b H_{3}$

Suggest Corrections

Similar questions

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

N H_{3} > P H_{3} > A s H_{3} > S b H_{3} > B i H_{3}

Join BYJU'S Learning Program