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Question

Reducing nature of the hydrides of group 15 follow the order

A
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B
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C
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D
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Solution

The correct option is A
As we descend the group, the size of the atom increases while the electronegativity decreases. So, can we say that Nitrogen exerts a greater degree of pull over the N – H bond than phosphorus in P – H bond? That seems logical! Further, with the increase in the size of the central atom, the orbital-orbital overlap between the element and Hydrogen will decrease.
Extending the logic further, can we infer that the strength of the E – H bond weakens as we go down the group? That is a correct assessment. As we go down the group, the bond dissociation energy decreases. In other words, the lower we go, the weaker the E – H bond! The weaker the E – H bond, the easier is the abstraction of Hydrogen. So the reducing nature of the hydrides increases as we go down the group.
AsH3 is more reducing that PH3 which is more reducing than NH3. So the increasing order of reducing nature is:
NH3<PH3<AsH3<SbH3<BiH3
The order of the stability is just the reverse

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