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Question

Reduction of the metal centre in aqueous permanganate ion involves

A
3 electrons in neutral medium
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B
5 electrons in neutral medium
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C
3 electrons in alkaline medium
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D
5 electrons in acidic medium
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Solution

The correct option is D 5 electrons in acidic medium
In acidic medium:
MnO4+5eMn2+(nfactor=5)
In strongly alkaline medium:
MnO4+eMnO24(nfactor=1)
In weakly basic and neutral medium:
MnO4+3eMnO2(nfactor=3)

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